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- Const. KingLv 71 month ago
A squared + B squared =C squared

11 + 5 = C squared

C = 4

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- lenpol7Lv 72 months ago
Use Pythagoras

BC^2 = (sqrt(5))^2 + (sqrt(11))^2

BC^2 = 5 + 11

BC^2 = 16

BC = sqrt(16)

BC = 4

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- billrussell42Lv 72 months ago
pyth. theorem

BC = √((√11)² + (√5)²) = √(11 + 5)) = √(16) = 4

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- A.J.Lv 72 months ago
a right triangle is A²+B²= C²

A is AB length, B is AC length, C is the BC hypotenuse.

The square of a square root is the number inside it.

This is an easy problem for those who know it, but the goal is for you to learn, so I just provided what you should need to answer it.

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